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23-12-2015
Mathematics

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Panoyin Panoyin · Answer 1 · 2015-12-23T14:01:16+01:00

      (x² - y²)² + (2xy)² = (x² + y²)²
   (x² - y²)(x² - y²) + 2x²y² = (x² + y²)(x² + y²)
      x²(x² - y²) - y²(x² - y²) + 2x²y² = x²(x² + y²) + y²(x² + y²)
x²(x²) - x²(y²) - y²(x²) + y²(y²) + 2x²y² = x²(x²) + x²(y²) + y²(x²) + y²(y²)
      x⁴ - x²y² - x²y² + y⁴ + 2x²y² = x⁴ + x²y² + x²y² + y⁴
         x⁴ - 2x²y² + y⁴ + 2x²y² = x⁴ + 2x²y² + y⁴
   x⁴ - 2x²y² + 2x²y² + y⁴ = x⁴ + 2x²y² + y⁴
      x⁴ + y⁴ = x⁴ + 2x²y² + y⁴
      - x⁴    - x⁴
   y⁴ = 2x²y² + y⁴
       - y⁴ - y⁴
      0 = 2x²y²
      2    2
      0 = x²y²
      0 = xy

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