the measures of the opposite angles of a parallelogram are equal
so
[tex]\text{ADC}=\text{ABC}[/tex]
and
[tex]DAB=\text{BCD}[/tex]
the sum of the total angles of a parallelogram is 360
so
[tex]\text{ADC}+\text{ABC}+\text{DAB+BCD=}360[/tex]
where ABC=ADC=66
and
BCD=DAB
so replacing
[tex]\begin{gathered} 66+66+\text{DAB}+\text{DAB}=360 \\ 132+2\text{DAB}=360 \end{gathered}[/tex]
now solve DAB
[tex]\begin{gathered} 2\text{DAB}=360-132 \\ \text{DAB}=\frac{228}{2} \\ \text{DAB}=114 \end{gathered}[/tex]
the measure of DAB is 114°
