Yes there is actually a formula for this. This is an arithmetic progression with a common difference of 1.
The sum of terms can be solved by using the formula
S = (n/2) * (a1 + an)
where S is the sum of the terms
n is the number of terms
a1 is the first term
an is the last term
we can calculate the number of terms, n by using the formula
an = a1 + (n-1)*d
d is the common difference equal to 1
therefore n = 51
substituting to the first equation
S = 2805
